Tolong bantu jawab pake caranya, makasi.
[tex] | \times - 1| + |2x| + |4x + 3| = 16 [/tex]
[tex] | \times - 1| + |2x| + |4x + 3| = 16 [/tex]
NilAI mutlak
|x| = a maka x = ± a
Penjelasan dengan langkah-langkah:
Nilai x :
|x - 1| + |2x| + |4x+ 3| = 16
x-1=0 --> x= 1
2x= 0 --> x= 0
4x+ 3= 0 ---> x = - 3/4
interval
i) x < -3/4
-(x - 1) - (2x) - (4x + 3) = 16
1 - x - 2x - 4x- 3= 16
-7x = 18
x = - 18/7 (memenuhi)
ii. -3/4 ≤ x < 0
(x - 1) - (2x) - (4x +3) = 16
x- 1 - 2x - 4x - 3 = 16
-5x = 20
x= - 4 (tm)
iii. 0 ≤ x < 1
(x - 1) + (2x) - (4x +3)= 16
x - 1 + 2X - 4x - 3 = 16
-x = 20
x = - 20 (tm)
iv. x > 1
( x- 1) + (2x) + (4x+ 3) = 16
x - 1 + 2x + 4x + 3 = 16
7x = 14
x= 2 (memenuhi)
HP dari |x - 1| + |2x| + |4x+ 3| = 16
x= -18/7 atau x = 2