Matematika Tolong bantu jawab pake caranya, makasi.
[tex] | \times - 1| + |2x| + |4x + 3| = 16 [/tex]

Tolong bantu jawab pake caranya, makasi.
[tex] | \times - 1| + |2x| + |4x + 3| = 16 [/tex]

NilAI mutlak

|x| = a maka  x = ± a

Penjelasan dengan langkah-langkah:

Nilai x  :

|x - 1| + |2x|  +  |4x+ 3| = 16

x-1=0 --> x= 1
2x= 0 --> x= 0
4x+ 3= 0 ---> x = - 3/4

interval
i) x <  -3/4

-(x - 1) - (2x) - (4x + 3) = 16

1 - x - 2x - 4x- 3= 16

-7x = 18

x = - 18/7  (memenuhi)

ii. -3/4  ≤ x < 0

(x - 1) - (2x) - (4x +3) = 16

x- 1 - 2x - 4x - 3 = 16
-5x = 20

x= - 4 (tm)

iii. 0 ≤ x < 1

(x - 1) + (2x) - (4x +3)= 16

x - 1 + 2X - 4x  - 3 = 16

-x  = 20

x = - 20 (tm)

iv. x > 1

( x- 1) + (2x)  + (4x+ 3) = 16
x - 1 + 2x + 4x + 3 =  16

7x = 14

x= 2 (memenuhi)

HP dari |x - 1| + |2x|  +  |4x+ 3| = 16
x=  -18/7   atau x = 2

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